i need help with terminal points >.< please help. i'll post the picture in a bit.
number 33
OK, you have some angle t and it has a terminal point as given there. If you use the terminal point, you can find the angle. OR you can use a little logic here.
\(\pi\) is half way around the unit circle. \(2\pi\) is all the way around. With just those facts, what can you say about any of the equations? Start with d. It is the easy one.
2pie-t= do i just substitute (3,5) or (4,5)??
The numbers in the point are fractions. They stay fractions.
(3/5) or (4/5)
This should help. A 1 unit circle, and the point \(\left(\frac{3}{5},\frac{4}{5}\right)\) on it. https://www.desmos.com/calculator/2kgjonrf8n
im still confuse >.<
You see the point and the circle, right? That is what they are taling about so lets start there.
okay
So there is some angle that goes along and makes that point the terminal. We don't know what it is, and we do not really care. What we want to know is where would the terminal point land if we added or subtracted things involving this angle. But not just anything. We want the known angles, \(pi\) and \(2pi\).
ohh okay
So if I draw in the angle's line, I get this: https://www.desmos.com/calculator/qa0oenlykq
Now... this is why I said d is the best one to start with. If I add \(2\pi\) to that angle, no matter what that angle is, where does the angle land?
quadrant 1?
Well, I meant a little more specific. Yes, in this case it is from Q1 back to Q1. But lets look a little closer. Heard the term coterminal angle used recently?
no
Ah. OK. If I start at 0 and I add \(2\pi\) I end up back at 0! This is the first coterminal angle people get to see. Because \(2\pi\) is a full revolution, the terminal point is the same!
Now, apply that principal to part d. What does that mean the terminal point is after you add \(2\pi\) to t?
that it'll be at the same place , 0?
For 0 the same place is 0. For some random angle that ends on \(\left(\frac{3}{5},\frac{4}{5}\right)\) it is?
((3/5),(4/5))
Exactly. Doing a drawing here cause it is easier to edit than desmos. |dw:1371940671934:dw|
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