Question

Find the vertex, focus, directrix, and focal width of the parabola
-1/16x^2 = y

Answer 1

\[-\frac{1}{16}(x-h)^2=y-k\]

Answer 2

What is the vertex?

Answer 3

0,0

Answer 4

@Mertsj

Answer 5

Multiply both sides by 16 and you will have it in the form:

Answer 6

(x−h)^2=4p(y−k)

Answer 7

Idk

Answer 8

When you have identified 4p, you can find p. Remember p is the distance from the vertex to the focus and also the distance from the vertex to the directrix.

Answer 9

You don't know what? How to multiply both sides by 16?

Answer 10

What are the two sides?

Answer 11

x=3
The two sides are:
left side = s
right side = 3
If I multiply both sides by 6, I will have 6x=18

Answer 12

I thought by 16?

Answer 13

@Mertsj

Answer 14

Did you multiply both sides by 16?

Answer 15

16s = 48

Answer 16

@Mertsj

Answer 17

Look at me.

Answer 18

I am. I'm really trying :(

Answer 19

Take your original equation that is given in the problem and multiply both sides by 16

Answer 20

16y = -x^2

Answer 21

now if you switch sides, it is of the form:

Answer 22

\[-x^2=4py\]

Answer 23

What is 4p?

Answer 24

P = 4

Answer 25

yes. p = 4. Does this one open up or down?