The altitude ( in feet ) attained by a model rocket t seconds into flight is given by the function: h(t) =- 1/3 t^3 + 4t^2 + 20t + 2, for t equal and greater 2. a. Find the maximum altitude attained by the rocket. Please, I need help. Do I need sketch the given graph ???
If you are familiar with calculus, then you would use derivatives to solve this If you are not familiar with calculus, then you would have to use a graphing calculator to solve
for your graphing calculator a good window is xmin = -4 xmax = 22 ymin = -340 ymax = 340
okay......you help me a lot.
after graphing, and possibly changing the window, you'll see this graph (see attached image)
Wow....that exactly the given graph shown in my paper question. LOL
that's good, glad they're both on the same page
to find the max, you would use your graphing calculators "max" function (or something like that)
Why does it not make sense to use this function after t = 16 seconds ???
what is the height after t = 16
eg: what's the height when t = 17?
undefined ????? lol
it's not undefined, notice how the red curve dips below the x axis right around t = 16
Yes
so the height is negative
but you can't have a negative height (well you could be below a certain marker, but usually a negative height makes no sense)
OMG........you right !!!
Now I can answer letter b question. Thank you Jim !!!
yw
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