Question

NEED SOMEONE TO SOLVE TO CHECK MY WORK second derivative of x^2 - y^2=16 dy/dx URGENT PLEASE THANK YOU

Answer 1

\[2x-2yy'=0\] solve for \(y'\)

Answer 2

oooh second derivative
first is
\[y'=\frac{x}{y}\] so you need the derivative of that one
use the quotient rule

Answer 3

\[y''=\frac{y-xy'}{y^2}\] then replace \(y'\) by \(\frac{x}{y}\)

Answer 4

dan, Question: how satelite73 has that y ' ?

Answer 5

thank you!!! exactly what I got

Answer 6

is it ok to simplify to 1-x dy/dx over y?

Answer 7

\[\large f(x)=x^2-y^2=16\]\[\large f'(x): 2x -2yy'=0\]\[\large f'(x): y'=\frac{x}{y}\]\[\large f''(x):y''=\frac{(1)y-xy'}{y^2}\]\[\large f''(x): y''=\frac{y-\frac{x}{y}}{y^2}\]\[\large f''(x):y''= \frac{\frac{y^2-x}{y}}{y^2}\]

Answer 8

x^2 - y^2=16dy/dx
(x^2 - y^2)/16= dy/dx

Answer 9

\[\large \frac{y^2-x}{y^3}= \frac{1}{y}-\frac{x}{y^3}\]

Answer 10

yes, i'm with you dan, how about dy/dx at the last place?

Answer 11

d^2y/dx^2=dy/dx[(x^2 - y^2)/16]

Answer 12

@Loser66 $$x^2-y^2=C\\\frac{d}{dx}[x^2-y^2]=0\\2x-2y\frac{dy}{dx}=0\\y\frac{dy}{dx}=x\\\frac{dy}{dx}=\frac{x}y\\$$

Answer 13

look at the problem, it has dy/dx after 16

Answer 14

i think that shudnt be there

Answer 15

@Loser66 the 2's get canceled out. and you're just left with x's and y's.

Answer 16

i did it with that dy/dx too lol

Answer 17

dy/dx means y w.r.t x. Or known as y prime= y'

Answer 18

without it, it's quite easy to understand

Answer 19

It's just a different format.

Answer 20

I'm not really sure what he's asking tbh

Answer 21

ya i thought he was asking
(x^2 - y^2)/16=dy/dx

Answer 22

differentials?

Answer 23

but i guess he just meant to say find
d^2/dx^2=?

Answer 24

I solved it the way you would solve a second derivative....

Answer 25

d^2y/dx^2=?

Answer 26

Dan, how about just y''. lol.

Answer 27

ok, there you go, shut up

Answer 28

we are going to get banned loser u and me!

Answer 29

The question is unclear. I wonder whether it is x^2-y^2 =16y' ?

Answer 30

loser go read a book

Answer 31

if it is just x^2 -y^2 =16. ha!! @dan815 yes sir

Answer 32

give it here?