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Mathematics 8 Online
OpenStudy (anonymous):

If a figure consists of 4 sides that are all congruent, then it is a parallelogram. Figure ABCD is a parallelogram. Therefore, ABCD has 4 congruent sides. Determine if the statement is valid.

OpenStudy (anonymous):

A.No,p-> q , q:p is an invalid argument. B.No,p -> q ,~p:~q is an invalid argument. C.Yes,p->q is true, therefore q is true. It is a valid argument.

jimthompson5910 (jim_thompson5910):

you got what?

OpenStudy (anonymous):

i got C.

jimthompson5910 (jim_thompson5910):

so you're saying that if p->q is true, then so is q->p ?

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

@jim_thompson5910 Am i wrong?

jimthompson5910 (jim_thompson5910):

unfortunately you are, it's invalid to say that the converse is equivalent to the original conditional

OpenStudy (anonymous):

:/ Darn it.

jimthompson5910 (jim_thompson5910):

think about it: If I told you that "Figure ABCD is a parallelogram", does this mean that it has all 4 sides congruent? the answer is "no" because some parallelograms do not have all 4 sides congruent

OpenStudy (anonymous):

So if its not C. then is No, p->q , is an invalid arguement.

jimthompson5910 (jim_thompson5910):

so which one, A or B?

OpenStudy (anonymous):

B?

OpenStudy (anonymous):

They both look the same to me though.

jimthompson5910 (jim_thompson5910):

they're not

jimthompson5910 (jim_thompson5910):

A is q -> p

jimthompson5910 (jim_thompson5910):

B is ~q -> ~p

OpenStudy (anonymous):

So my answer was A?

jimthompson5910 (jim_thompson5910):

one is the converse, the other is the contrapositive

jimthompson5910 (jim_thompson5910):

yeah it's A

OpenStudy (anonymous):

so its the converse.A.

jimthompson5910 (jim_thompson5910):

oh wait, they've formatted it differently, one sec

jimthompson5910 (jim_thompson5910):

A is still correct, I was just using different notation

OpenStudy (anonymous):

ok. thanks Jimmy.(:

jimthompson5910 (jim_thompson5910):

yw

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