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OpenStudy (anonymous):

Can anyone explain why the change of entropy of free adiabetic expansion is not zero?i mean since there is no heat entering the system ,the entropy does not change,right?

OpenStudy (anonymous):

Sorry, but you are not right. Actually, when the gas expands its molecules get more separated from each other and that's why randomness increases and hence the entropy. That's what I think about it, it might not be exact, but it can't be completely wrong.

OpenStudy (shamim):

here, change of entropy is\[dS\]

OpenStudy (shamim):

change of heat\[dQ\] is

OpenStudy (shamim):

the formula is\[dS=\frac{ dQ }{ T }\]

OpenStudy (shamim):

\[T\]is temperature in kelvin scale

OpenStudy (shamim):

in adiabatic process \[dQ=0\]

OpenStudy (shamim):

so\[dS=\frac{ 0 }{ T }=0\]

OpenStudy (shamim):

so in adiabatic process change of entropy is 0

OpenStudy (anonymous):

Thanks for your replies That is actually what I think ,but in most physics text books they said the entropy has increased ,so which one is right?(the second law of thermodynamics says that any irreversible process has a change of entropy bigger than zero)

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