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Mathematics 19 Online
OpenStudy (anonymous):

Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form.

OpenStudy (jdoe0001):

what's the slope of the equation -> y = 4x + 7 ?

OpenStudy (anonymous):

wud 7 be the slope

OpenStudy (anonymous):

4 wud be slope

OpenStudy (jdoe0001):

ok, so your other line is PERPENDICULAR to this one

OpenStudy (jdoe0001):

bearing in mind that perpendicular lines have NEGATIVE RECIPROCAL slopes so if this one has a a slope of "4" the other slope would be reciprocal of 4 1/4 negativize that -1/4

OpenStudy (jdoe0001):

so, now you know it passes through (2, -3) and has a slope of -1/4 to get the line, use the point-slope form and solve for "y" http://www.coastal.edu/mathcenter/HelpPages/Line(Point-Slope)/img002.GIF

OpenStudy (anonymous):

the point slope wud be ? -1/4

OpenStudy (jdoe0001):

ahemm, read above

OpenStudy (jdoe0001):

the example in the picture, shows how to use the point-slope form :)

OpenStudy (anonymous):

ok so -1/4 is my slope

OpenStudy (anonymous):

no 4 is my slope

OpenStudy (jdoe0001):

you have 2 lines, you have the equation for one " y = 4x + 7" and you only know about the OTHER LINE that it passes through (2, -3) and is perpendicular to the line " y = 4x + 7"

OpenStudy (jdoe0001):

if y = 4x + 7 has a slope of "4" the perpendicular line to it will have a slope of NEGATIVE RECIPROCAL of 4

OpenStudy (anonymous):

i got y=4x-5 so far

OpenStudy (anonymous):

|dw:1372011912269:dw|

OpenStudy (jdoe0001):

|dw:1372012261296:dw|

OpenStudy (jdoe0001):

4 is the slope of the GIVEN line the slope of the perpendicular line that passes through (2, -3) is -1/4

OpenStudy (anonymous):

so i just forgot the -1/4

OpenStudy (jdoe0001):

yes, the rest of the procedure is good though, just need to change the 4 to -1/4

OpenStudy (anonymous):

okay so will my final y=4x-5 will tht be changed to y=-4x-5?

OpenStudy (jdoe0001):

$$ \text{what do you get from}\\ y-(-3) = -\cfrac{1}{4}(x-2) $$

OpenStudy (anonymous):

a negative

OpenStudy (jdoe0001):

ahemm, yes the slope will be negative, meaning the function is "descending"

OpenStudy (anonymous):

so y = -4x-5

OpenStudy (jdoe0001):

if you just solve \(\large y-(-3) = -\cfrac{1}{4}(x-2) \) for "y", you'd know :)

OpenStudy (anonymous):

when i did tht i got y+3=-2.25

OpenStudy (jdoe0001):

well, the "x" seem to have got the axe hehe

OpenStudy (anonymous):

|dw:1372012836427:dw|

OpenStudy (anonymous):

-1/4x

OpenStudy (anonymous):

well a negative plus a negative wud be a positive number. So I believe it would become positive.

OpenStudy (jdoe0001):

$$ \text{what do you get from} y-(-3) = -\cfrac{1}{4}(x-2)\\ \implies y+3 = -\cfrac{1}{4}x+\cfrac{2}{4} \implies y+3 = -\cfrac{1}{4}x+\cfrac{2}{4}\\ \implies y = -\cfrac{1}{4}x+\cfrac{1}{2}-\color{blue}{3}\\ \color{blue}{3 = \cfrac{6}{2}}\ \ thus\\ \implies y = -\cfrac{1}{4}x+\cfrac{1}{2}-\color{blue}{\cfrac{6}{2}}\\ \color{green}{y = -\cfrac{1}{4}x-\cfrac{5}{2}} $$

OpenStudy (anonymous):

wud the y=4x-5 be the final answer

OpenStudy (jdoe0001):

that's the line

OpenStudy (anonymous):

Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7

OpenStudy (anonymous):

okay so then y=-1/4x-5/2 is the final aswer

OpenStudy (jdoe0001):

yes

OpenStudy (anonymous):

and yes i saw they were perpendicular. thank u!

OpenStudy (jdoe0001):

yw

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