Question

(x-5)(x+3)=33 ; find the real roots

Answer 1

(x-5)(x+3)=33
x^2 - 2x - 15 = 33
x^2 - 2x - 48 = 0

can u continue from here?

Answer 2

Thanks! Just realized my mistake. added 33 instead of subtracting

Answer 3

yw

Answer 4

Ah another question. Havent done this stuff in 4 years.

Answer 5

(x+2)^2(x-1)+(x+2)(x-1)^2

Answer 6

\[(x+2)^2(x-1) + (x+2)(x-1)^2\]multiply it out, step by step:
\[(x+2)^2 = (x+2)(x+2) = x^2+2x+2x+4 = x^2+4x+4\]
\[(x^2+2x+4)(x-1) = x^3-x^2+2x^2-2x+4x-4 = x^3+x^2+2x-4\]
\[x^3+x^2+2x-4 + (x+2)(x-1)^2\]you do the rest, then simplify

Answer 7

I've gotten down to 2x^3+3x^2-11x-2

Any help factoring that please?

Answer 8

@cwrw238 pretty sure that those 2s outside parentheses are supposed to be ^2

Answer 9

yea - u r right

Answer 10

i'm embarrassed!!

Answer 11

life would be easier if openstudiers couldn't copy and paste the questions, losing all of those valuable positional clues :-)

Answer 12

yea

Answer 13

Guys , you didnt need to expand!

Answer 14

we didn't need to do anything, really :-)

Answer 15

just do something similar like a^2v +ab^2 = ab(a+b) then solve!

Answer 16

gah im hitting myself >:(