Question

Am i right?

Answer 1

for \[S=2\pi rh+2\pi r ^{2}\]

Answer 2

solve for h

Answer 3

i got S−2πr2/2πr=h

Answer 4

difficult to determine due to lack of parenthesis

Answer 5

am i supposed to trust you because your username.. @completeidiot

Answer 6

putting my name aside

that you have written would be

\[S- \frac{2\pi r ^2 }{2 \pi r } = h\]

Answer 7

which i will add is incorrect

Answer 8

S is and the - sign is also in the numerator @completeidiot

Answer 9

(S−2πr2)/2πr=h
will look like
\[\frac{ S- 2 \pi r^2 }{2 \pi r} = h\]

Answer 10

sorry it should be

(S−2πr2)/(2πr)=h

Answer 11

parenthesis are important when you have fractions and need to group the numerator and the denominators together

but yes you are correct

Answer 12

oh okay thank you @completeidiot

Answer 13

no prob

Answer 14

could you help me with a couple of others also? @completeidiot
I dont get some of them @completeidiot

Answer 15

close this question and open a new one

im sure plenty of people here will be able to help you as well