3. Find (-4x)^2
4. Multiply and simplify (x-3)(x+2)
5.Factor out the largest possible common factor 3xyz+8xy^2
6. Factor as much as possible: x^2+10x+25
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OpenStudy (anonymous):
3 would be 16x^2 correct?
OpenStudy (anonymous):
4 would be x^2-1
OpenStudy (anonymous):
3) 16x^2
4) x^2-x-6
5) xy(3z+8y)
6) (x+5)^2 or (x+5)*(x+5)
OpenStudy (anonymous):
#4 is not as simple as says x*x + (-3+2) = x^-1
are you familiar with FOIL?
OpenStudy (anonymous):
Yeah sort of
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jimthompson5910 (jim_thompson5910):
robz8 don't just give out answers
it's against the code of conduct
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
I dont' understand how you do 5. I came up with a different answer for that
OpenStudy (anonymous):
I see where I messed up with 4 by using foil.
jimthompson5910 (jim_thompson5910):
to factor x^2+10x+25, you look for two numbers that
a) multiply to 25 (last term)
AND
b) add to 10 (middle coefficient)
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jimthompson5910 (jim_thompson5910):
the two numbers are 5 and 5
5+5 = 10
5*5 = 25
so this means x^2+10x+25 factors to (x+5)(x+5)
OpenStudy (anonymous):
so you have 3xyz+8xy^2
both those terms have "xy" in common about them, so you can 'factor' them out
jimthompson5910 (jim_thompson5910):
since you have a copy of the same factor, you can condense (x+5)(x+5) into (x+5)^2
jimthompson5910 (jim_thompson5910):
oh sry, saw the wrong one...
OpenStudy (anonymous):
I got 2x(yz+4y^2
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jimthompson5910 (jim_thompson5910):
2 is a factor of 8, but not of 3
jimthompson5910 (jim_thompson5910):
so 3xyz+8xy^2 doesn't factor to 2x(yz+4y^2)
OpenStudy (anonymous):
I'm sorry its not supposed to be 3 its supposed to be 2*
jimthompson5910 (jim_thompson5910):
ah ok
jimthompson5910 (jim_thompson5910):
2xyz+8xy^2
2x(yz+4y^2)
that's a good start, but you can factor more
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jimthompson5910 (jim_thompson5910):
you can pull out y as well
jimthompson5910 (jim_thompson5910):
what do you get when you do that
OpenStudy (anonymous):
2x(z+4y)
jimthompson5910 (jim_thompson5910):
when you pull out the y, it goes outside the parenthesis
jimthompson5910 (jim_thompson5910):
so you should have this
2xy(z+4y)
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OpenStudy (anonymous):
Ohhh ok
jimthompson5910 (jim_thompson5910):
as a check, you can distribute back through and you should get the original expression as a result