Question

evaluate

Answer 1

solve what ? ;o

Answer 2

nevermind i see it now .-.

Answer 3

\(\frac{ 1 }{ \sqrt{2} +1 }+\frac{ 1 }{ \sqrt{3}+\sqrt{2}}+\frac{ 1 }{ \sqrt{4}+\sqrt{3} }+\frac{ 1 }{ \sqrt{9}+\sqrt{8}}\)

Is this your question? :)

Answer 4

\[\frac{ 1 }{ \sqrt{2} +1 }+\frac{ 1 }{ \sqrt{3}+\sqrt{2}}+\frac{ 1 }{ \sqrt{4}+\sqrt{3} }+\frac{ 1 }{ \sqrt{9}+\sqrt{8}}\]

Answer 5

yes

Answer 6

but there is only one error , for that, plse see the attah file

Answer 7

Any options? or is this essay?

Answer 8

\[\large\frac{1}{\sqrt{n+1}+\sqrt{n}}\]

Answer 9

lol i dont understand with that line Jhan xD

Answer 10

Seems like this would be it..... where n is any number...starting from 1.... \(\rightarrow\)9

Answer 11

which line?

Answer 12

when n=1 \[\large \frac{1}{\sqrt{1+1}+\sqrt{1}}= \frac{1}{\sqrt{2}+1}\] etc.

Answer 13

when n=2 \[\large \frac{1}{\sqrt{2+1}+\sqrt{2}}\]

Answer 14

yes @Jhannybean
u r right its .starts from 1.... →9

Answer 15

Is it a series? To see whether it converges/diverges?

Answer 16

the question was just to evaluate the value

Answer 17

:\ awkward.i'm not sure.....

Answer 18

@experimentX

Answer 19

multiply by conjugate

Answer 20

1/rt2+rt1+1/rt3+rt2+1/rt4+rt3+1/rt5+rt4
tn=1/rtn+1+rtn
rationalize
tn=rt(n+1)-rtn
t1=rt2-rt1
t2=rt3-rt2
t3=rt4-rt3
t4=rt5-rt4
t5=rt6-rt5
t6=rt7-rt6
t7=rt8-rt7
t8=rt9-rt8
s8=rt9-rt1=3-1=2

Answer 21

omg...

Answer 22

Parenthesis would help!