Question

Indicate in standard form the equation of the line passing through the given points.

B(0, 0), C(4, -4)

Answer 1

please help
!!

Answer 2

equation of line which go through 2 points is\[y-y _{1}=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }(x-x _{1})\]

Answer 3

here \[x _{1}=0,y _{1}=0,x _{2}=4,y _{2}=-4\]

Answer 4

just put these value in above equation

Answer 5

did u get it

Answer 6

y- -4 = x-0

Answer 7

no

Answer 8

\[y-0=\frac{ -4-0 }{ 4-0 }(x-0)\]

Answer 9

oh i pluged them in wrong

Answer 10

y-0= -4/4(x-0)

Answer 11

ya

Answer 12

then?

Answer 13

does -4/4 = 0 or -1

Answer 14

-1

Answer 15

anyway\[-4+4=0\]

Answer 16

but\[\frac{ -4 }{ 4 }=-1\]

Answer 17

\[\frac{ 4 }{ 4 }=1\]

Answer 18

y-0=-1x-(-1)

Answer 19

no

Answer 20

i m showing u every steps

Answer 21

\[y-0=\frac{ -4-0 }{ 4-0 }(x-0)\]

Answer 22

\[y=\frac{ -4 }{ 4 }x\]

Answer 23

\[y=-1x\]

Answer 24

\[y=-x\]

Answer 25

\[y+x=0\]

Answer 26

\[x+y=0\]

Answer 27

feel free to ask any question

Answer 28

thank you for helping me

Answer 29

welcome

Answer 30

do you know how to do this Indicate the equation of the given line in standard form.

The line containing the diagonal of a square whose vertices are A(-3, 3), B(3, 3), C(3, -3), and D(-3, -3). Find two equations, one for each diagonal.

Answer 31

ya i can solve it

Answer 32

bt u should post ur in ask a question box

Answer 33

anyway i m solving it

Answer 34

so ur 1 line will go through A(-3,3) and C(3,-3)

Answer 35

im sorry my first time on this

Answer 36

its one diagonal

Answer 37

its ok

Answer 38

its what

Answer 39

sorry for late

Answer 40

anyway i was solving another math

Answer 41

now ur 1 line will go through A(-3,3) and C(3,-3)

Answer 42

so the formula for ur diagonal line will b\[y-y _{1}=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }(x-x _{1})\]

Answer 43

here \[x _{1}=-3,y _{1}=3,x _{2}=3,y _{2}=-3\]

Answer 44

so\[y-3=\frac{ -3-3 }{ 3-(-3) }(x-(-3))\]

Answer 45

now solve it

Answer 46

did u get it