On a 10 question multiple-choice test, where each question has four answers, what would be the probability of getting at least one question wrong?
What's the probability of getting them all correct?
9.5367x10^-7
so basically 0.00000095367431
the probability of getting at least one wrong is one minus this answer because the two events are complementary
one or the other must happen
so this means P(getting at least one wrong) = 1-P(getting them all right) P(getting at least one wrong) = 1-0.00000095367431 P(getting at least one wrong) = 0.9999990463257
so it looks very likely you're going to get at least one wrong
I thought that that would be right, but I am working the problem for an online class and the computer is saying the answer is incorrect....Maybe its a technicality in how I am entering it.
do they want it as a decimal? or a fraction?
all of my other answers have been correct when entered as decimals as long as they are carried out to the fourth decimal place. I have entered 0.9999 and it is saying that is wrong.
this may sound stupid, but 0.9999990463257 rounded to 4 decimal places is 1.0000
so that's why I'm thinking they either want more decimal places or they want it as a fraction
if they want it as a percentage then 0.9999990463257 ---> 0.9999990463257*100 = 99.99990463257% so, 0.9999990463257 = 99.99990463257%
I tried it as a percentage and that won't work either. I guess I will have to talk with the professor and see what I am doing wrong. Thank you for your help.
can you post a screenshot of the entire problem so I can have a look?
there may be some key detail missing
I'm curious, but have you tried 9999/10000 at all?
no I haven't tried that
that's the answer as a fraction, you basically evaluate 1 - (1/(10^4)) to get that
if neither the decimal or percent forms are working, then it has to be a fraction btw I don't see any piece of info that helps, so maybe there's more context elsewhere, idk?
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