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Mathematics 19 Online
OpenStudy (anonymous):

suppose a population of 50 crickets doubles in size every 4 months. how many crickets will there be after 5 years?

OpenStudy (dmezzullo):

Ok so there is 12 months in a year correct?

OpenStudy (anonymous):

First of all, Welcome to OpenStudy :D

OpenStudy (anonymous):

yes

OpenStudy (dmezzullo):

Ok so then 5x12 is 60 so divide 60 into 4

OpenStudy (anonymous):

thats 15

OpenStudy (anonymous):

but my answer choices is in the thousands

OpenStudy (dmezzullo):

Shoot my dyslexia got the best of me

OpenStudy (dmezzullo):

Lemme redo that

OpenStudy (anonymous):

We should know: 1 year = 12 months Given: Doubles every 4 months So: 4 * 3 =12 Therefore: 1 year, there is 3 sets of 4 months. Hence: 4 * 3 = 12 Then: 2 years have 6 sets of 4 months. 3 years have 9 sets of 4 months 4 years have 12 sets of 4 months 5 years have 15 sets of 4 months Good so far?

OpenStudy (anonymous):

\i did all that but i confused myself

OpenStudy (anonymous):

We start with a population of 50 crickets So then: \[50 \times 2^{n}\] \[50 \times 2^{15}\] whats 2^15? after u get that, multiply what you got from that by 50. Try it and let me see what you get. :)

OpenStudy (anonymous):

50 X 2^15 is 1638400

OpenStudy (whpalmer4):

yes, that's correct. is that one of your answer choices?

OpenStudy (anonymous):

^ yes good.

OpenStudy (anonymous):

So: \[1,638,400\] Is that an answer choice? @roxxy251

OpenStudy (anonymous):

You were on the right path @dmezzullo :)

OpenStudy (dmezzullo):

That stuff is easy for me but dyslexia dont help

OpenStudy (anonymous):

it was on my quiz, i go it wrong by puttin 1500 buti believe that was 1 of my answer choices,im doing school online, and ihova another question also

OpenStudy (anonymous):

Another question from ur quiz?

OpenStudy (whpalmer4):

@roxxy251 just to clarify, are these problems that you got wrong on the quiz?

OpenStudy (anonymous):

yes these the problem i had wrong on the quiz

OpenStudy (whpalmer4):

okay. I'm not interested in helping someone take a quiz, but happy to explain after the fact.

OpenStudy (anonymous):

yep ^

OpenStudy (whpalmer4):

what was the next one you got wrong? if you can explain what your wrong answer was, and how you got it, that would be great — wouldn't have to worry that you were trying to pull a fast one.

OpenStudy (anonymous):

again, yep ^

OpenStudy (whpalmer4):

and we promise not to laugh :-)

OpenStudy (anonymous):

suppose an investment of $8,200 doubles in value every 7 years. how much is the investment worth after 28 years

OpenStudy (whpalmer4):

how many doublings is that?

OpenStudy (anonymous):

4

OpenStudy (whpalmer4):

right. and what is 2*2*2*2?

OpenStudy (anonymous):

16

OpenStudy (whpalmer4):

and 16 * 8200?

OpenStudy (anonymous):

yep ^

OpenStudy (anonymous):

131200

OpenStudy (anonymous):

its kinda the same concept as your 1st question

OpenStudy (whpalmer4):

so how did you get it wrong?

OpenStudy (anonymous):

@roxxy251 what did you put as your answer; which was wrong according to you?

OpenStudy (anonymous):

86,000 i used the wrong formula and how you putting it make it seemd a whole lot easier, thanks

OpenStudy (whpalmer4):

well, I try :-)

OpenStudy (anonymous):

r u very good n math

OpenStudy (anonymous):

lol yes @whpalmer4 is quite good; very good, in math :3

OpenStudy (anonymous):

Alot of ppl here are!

OpenStudy (anonymous):

okay im having problems with exponential growth and decay

OpenStudy (whpalmer4):

okay, let's have one of those problems.

OpenStudy (anonymous):

u still there

OpenStudy (whpalmer4):

I am.

OpenStudy (anonymous):

this is home work now, and i still dont understand this at all . but the question is, a boat costs 16,600 an decreases in value per 14% per year. how much will the boat be worth after 11 years

OpenStudy (whpalmer4):

Okay. present value is $16,600. Decreases by 14% each year. 14% = 14% * 1/100% = 0.14, right? If we start with 1, and subtract 14%, that's 1-0.14 = 0.86. After 1 year, the boat is worth 0.86 * purchase price. After 2 years, the boat is worth how much?

OpenStudy (anonymous):

14276

OpenStudy (anonymous):

ugh i feel dumb

OpenStudy (anonymous):

i hate math

OpenStudy (whpalmer4):

No, it's worth that much after 1 year. At the end of 1 year, it has decreased by 14%, which is the same as saying it is worth 86% of its previous value. Each passing year, we'll multiply by 86% again. After n years, the value will be the starting value * 0.86^n — do you see why that is?

OpenStudy (anonymous):

no ,n itsmaking me very upset

OpenStudy (whpalmer4):

Okay, do you see why multiplying by 0.86 is the same as decreasing 14%?

OpenStudy (anonymous):

nope

OpenStudy (whpalmer4):

what do you think it means to decrease by 14%?

OpenStudy (anonymous):

less than

OpenStudy (whpalmer4):

how much?

OpenStudy (whpalmer4):

If I have 100 dollars, and it decreases by 14%, how much do I have left?

OpenStudy (anonymous):

im not really good with percentages,

OpenStudy (whpalmer4):

percent just means "out of 100" 14 percent means 14 out of 100.

OpenStudy (anonymous):

okay so basically divide 14 over a 100 or subtract 14and 100

OpenStudy (whpalmer4):

if we decrease something by 14%, it means we chop it up into 100 equal pieces, and get rid of 14 of them.

OpenStudy (whpalmer4):

that leaves us with 86 of those pieces

OpenStudy (whpalmer4):

so decreasing by 14% over and over means keeping only 86% over and over...

OpenStudy (anonymous):

okay now w/ that problem i suppose to do what

OpenStudy (whpalmer4):

well, you wanted to find out how much the boat is worth after some number of years of depreciation at 14% per year. the value of the boat is going to be the starting value (what ou paid for it) * 0.86 after one year, starting value * 0.86 * 0.86 after two years, starting value * 0.86 * 0.86 * 0.86 after three years, and so on: \(16,600*0.86^n\) where \(n\) is the number of years.

OpenStudy (whpalmer4):

in this case, we want to find how much it is worth after n=11 years. your calculator probably has a y^x button, so you enter 0.86, press y^x, then enter 11, then press * 16600 =

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