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Mathematics 18 Online
OpenStudy (anonymous):

sin(-x)=-sin x for all values of x true or false.

terenzreignz (terenzreignz):

Proving identities often involves turning one side into another using some known identities. Perhaps use the fact that \[\Large -x = 0-x\] and \[\Large \sin(a - b) = \sin(a)\cos(b)-\cos(a)\sin(b)\]

terenzreignz (terenzreignz):

Not to mention \[\large \sin(0)=0\\\large \cos(0)=1\]

OpenStudy (anonymous):

so its true

terenzreignz (terenzreignz):

Find out. As per those identities, what is \[\Large \sin(-x) = \sin(0-x)=\color{red}?\]

OpenStudy (anonymous):

true

OpenStudy (anonymous):

sources : http://www.wolframalpha.com/input/?i=sin%28-x%29%3Dsin%280-x%29

OpenStudy (anonymous):

Thanks :)

terenzreignz (terenzreignz):

I'm certain you're not allowed to use that resource :3 Come on... \[\Large \sin(\color{red}a-\color{blue}b) = \sin(\color{red}a)\cos(\color{blue}b) - \cos(\color{red}a)\sin(\color{blue}b)\\\Large \sin(\color{red}0-\color{blue}x) = \sin(\color{red}0)\cos(\color{blue}x) - \cos(\color{red}0)\sin(\color{blue}x)\]

terenzreignz (terenzreignz):

and knowing that sin(0) = 0 and cos(0) = 1 you get the identity you need.

OpenStudy (anonymous):

Yes it is true for all values of x.

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