sin(-x)=-sin x for all values of x true or false.
Proving identities often involves turning one side into another using some known identities. Perhaps use the fact that \[\Large -x = 0-x\] and \[\Large \sin(a - b) = \sin(a)\cos(b)-\cos(a)\sin(b)\]
Not to mention \[\large \sin(0)=0\\\large \cos(0)=1\]
so its true
Find out. As per those identities, what is \[\Large \sin(-x) = \sin(0-x)=\color{red}?\]
true
Thanks :)
I'm certain you're not allowed to use that resource :3 Come on... \[\Large \sin(\color{red}a-\color{blue}b) = \sin(\color{red}a)\cos(\color{blue}b) - \cos(\color{red}a)\sin(\color{blue}b)\\\Large \sin(\color{red}0-\color{blue}x) = \sin(\color{red}0)\cos(\color{blue}x) - \cos(\color{red}0)\sin(\color{blue}x)\]
and knowing that sin(0) = 0 and cos(0) = 1 you get the identity you need.
Yes it is true for all values of x.
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