Question

The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)

Indicate the equation of the given line in standard form.

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

help

Answer 1

so u hv 2 questions. is not it

Answer 2

for ur 1st math

Answer 3

ur given equation of line is\[y-4=\frac{ 2 }{ 3 }(x-3)\]

Answer 4

\[y=\frac{ 2 }{ 3 }x-2+4\]

Answer 5

\[y=\frac{ 2 }{ 3 }x+2\]

Answer 6

now u hv to compare this given equation of line with standard equation of line which is \[y=mx+c\]

Answer 7

so the slope of ur given line is\[m=\frac{ 2 }{ 3 }\]

Answer 8

slope of any parralel line is same

Answer 9

so slope of a parallel line will b\[m=\frac{ 2 }{ 3 }\]

Answer 10

this parallel line will go through a point (1,-2)

Answer 11

u know the equation of line is\[y-y _{1}=m(x-x _{1})\]

Answer 12

here\[x _{1}=1,y _{1}=-2\]

Answer 13

so the equation of ur parallel line is\[y-(-2)=\frac{ 2 }{ 3 }(x-1)\]

Answer 14

now try to solve it

Answer 15

did u get it

Answer 16

im solving it :)

Answer 17

ok

Answer 18

write the result

Answer 19

well im stuck y-2=2/3x-2/3

Answer 20

no

Answer 21

\[y+2=\frac{ 2 }{ 3 }(x-1)\]

Answer 22

\[3y+6=2x-2\]

Answer 23

do the rest

Answer 24

3y=2x-8
or
2x-3y=8

Answer 25

if u feel any difficulties then ask me please

Answer 26

ya u r correct

Answer 27

i am :D yay :)

Answer 28

2x-3y=8 so its that

Answer 29

ya

Answer 30

thank you

Answer 31

welcome

Answer 32

bt u hv another math here

Answer 33

oh yeah

Answer 34

2nd portion of ur math