Question

1/x-1/y/1/x+1/y

Answer 1

Is the question
(i) \(\frac{1}{x} - \frac{\frac{1}{y}}{\frac{1}{x}} + \frac{1}{y}\)
or
(ii) \(\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}\)
or
(iii) other (please specify clearly)
?

Answer 2

its (ii)

Answer 3

multiply to get a common denominator

Answer 4

First, find \(\frac{1}{x} - \frac{1}{y}\). Can you do it?

Answer 5

is it \[1x/xy-1x/xy\]

Answer 6

\[\frac{1}{x}-\frac{1}{y}\]\[=\frac{1}{x}\times\frac{y}{y}-\frac{1}{y}\times\frac{x}{x}\]\[=\frac{y}{xy}-\frac{x}{xy}\]\[=...?\]

Answer 7

final answer would be -1 ?

Answer 8

got it! thank you :)

Answer 9

The answer is not -1.

Answer 10

oh

Answer 11

everything crosses out except a negative?

Answer 12

Please show your steps.

Answer 13

I get a common denominator for the top part and bottom
and then it says divide so I do the reciprocal and multiply but I can cross stuff out which only leaves a negative

Answer 14

What have you got for \(\frac{1}{x} - \frac{1}{y}\) and \(\frac{1}{x} + \frac{1}{y}\) respectively?

Answer 15

i get \[y/xy - x/xy\]
then divided by \[y/xy + x/xy\]

Answer 16

then the reciprocal of the bottom part multiplied with the top

Answer 17

Combine \(\frac{y}{xy} -\frac{x}{xy}\) into \(\frac{y-x}{xy}\)

Can you do the same for \(\frac{y}{xy} +\frac{x}{xy}\)?

Answer 18

ohhhhh okay thank you! y-x/y+x

Answer 19

Yes :)

Answer 20

Next time please make use of the parentheses  in typing the question.
[ (1/x) - (1/y) ] / [ (1/x) + (1/y) ]
Or you can use LaTeX

Answer 21

hahah okay i sure will