Question

I need to rewrite a formula

Answer 1

\(\huge q=\left(\frac{25}{25+8.8*10}\right)^3~=\LARGE 0.0108\)

Now i need to calculate what's 10 in this one for another formula without the 3th powe.
\(\LARGE 0.0108\huge =\left(\frac{25}{25+8.8*V_{org}}\right)\)

I know the answer is 260 by solving for x but how to rewrite this formula to get V org before the equal sign.
I was thinking of this:
\(\huge V_{org}=\frac{\left(\Huge\frac{25}{25+8.8}\right)}{0.0108}\)

But it gives me the wrong answer.
What did i do wrong?

Answer 2

\[\LARGE 0.0108\huge =\left(\frac{25}{25+8.8*V_{org}}\right)\]

\[\LARGE 25+8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)\]

\[\LARGE 25+8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)\]

\[\LARGE 8.8*V_{org}\huge =\left(\frac{25}{0.0108}\right)-25\]

\[\LARGE V_{org}\huge =dfrac{\left(\frac{25}{0.0108}\right)-25}{8.8}\]

Answer 3

neglect last one sorry

Answer 4

\[\LARGE V_{org}\huge =\dfrac{\left(\frac{25}{0.0108}\right)-25}{8.8}\]

Answer 5

^^That could give you Vorg

Answer 6

Yes it does :)
Thanks man

Answer 7

yw :)