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If complex number z=4-6i,then |z-2|= ?
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\[z=4-6i\]
\[z-2=4-6i-2=2-6i\]
\[|z-2|=\sqrt{2^{2}+(-6)^{2}}\]
now try it
Im confused... Can you llease explain the process?
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where u confused
Where you took a square root of 2-6i
its rule of mode
its law of modulus
i took modulus on left side n root on right side
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Oh i thought the sticks were absolute value signs... Thanks anyway
welcome
it is the same
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