Hello. I don't understand how to find a point on the terminal angle when you are given a degree. Can anyone help?
Hello :) I'm sorry but I am still confused I looked over that and did not see anything about a terminal angle and finding a point. Sorry!
Can someone please try to explain it to me?
this might help http://www.khanacademy.org/math/trigonometry/basic-trigonometry/unit_circle_tut/v/unit-circle-definition-of-trig-functions-1
the ordered pair (r,\(\theta\)) represents how far you turn "\(\theta\)" by how far you move from the origin "r".
other than that, what is it that is confusing you about it?
What if I am not given r? In my book it asks for example " θ=45 degrees choose a point on the terminal side" It then gives the choices "(2,2) (1,(rad)3) ((rad)3, 1)" I can not understand for the life of me why the answer is (2,2)
if we make a 45 degree angle with the positive x axis|dw:1372076097058:dw| we produce a line thru the origin with a slope of tan(45) = 1 y = x
which one of the given points is on that line?
another way to look at it is: tangent and slope are both defined by y/x so they are the same thing. which point has an inverse tangent of 45 degrees? tan(a) = y/x a = \(tan^{-1}(2/2)\) a = \(45^o\)
wait so if I do tan-1 would that work with any example or just this one? Also what if it is a larger angle or a negative? But for another question basically I just graph and look?
the line produced by the angle will always have the basic form: y = mx since m = tan(a) = y/x , then filling in the line equation is a matter of taking the inverse tangent of a given point. so yes, if you know how to graph the angle then you can determine any point along the line that is formed
if just given a degree, then replace m by tan y = tan(45) x y = 1x
y = tan (m)x ? Then how do I know y and x? I think I am missing something simple. I'm sorry.
you determine y and x from given options. the key is relating the trig function "tangent" to the definition of the slope of a line "m". slope is defined as y/x tangent is defined as y/x lets use a 60 degree angle for an example, we want to determine the equation: y = mx y = tan(a) x y = tan(60) x y = sqrt(3)/1 x this is the usual form of a line that everyone is fond of seeing. now we can take any of the given points and test if they fit the line does 2,2 fit?: 2 = sqrt(3) * 2 = 2sqrt(3) since 2 does not equal 2sqrt(3) this point is not a line of 60 degrees does 1, sqrt(3): sqrt(3) = sqrt(3) * 1 = sqrt(3) since sqrt(3) equals sqrt(3) this point IS on a line of 60 degrees.
the inverse tangent method would also suffice: you are given that: m = y/x tan(45) = y/x 45 = tan^-1 (y/x) test out the given points. it might help to recall that a point is defined as (x,y)
so if I can plug it in equal to the y and it doesn't work then it isn't right. I'm going to try an example could you tell me if I did it correctly?
Thank you! I figured out! :)
yay! :) i think the site went down for a bit the last time ....
Join our real-time social learning platform and learn together with your friends!