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Mathematics 9 Online
OpenStudy (katara11111):

Hello. I don't understand how to find a point on the terminal angle when you are given a degree. Can anyone help?

OpenStudy (anonymous):

OpenStudy (katara11111):

Hello :) I'm sorry but I am still confused I looked over that and did not see anything about a terminal angle and finding a point. Sorry!

OpenStudy (katara11111):

Can someone please try to explain it to me?

OpenStudy (amistre64):

the ordered pair (r,\(\theta\)) represents how far you turn "\(\theta\)" by how far you move from the origin "r".

OpenStudy (amistre64):

other than that, what is it that is confusing you about it?

OpenStudy (katara11111):

What if I am not given r? In my book it asks for example " θ=45 degrees choose a point on the terminal side" It then gives the choices "(2,2) (1,(rad)3) ((rad)3, 1)" I can not understand for the life of me why the answer is (2,2)

OpenStudy (amistre64):

if we make a 45 degree angle with the positive x axis|dw:1372076097058:dw| we produce a line thru the origin with a slope of tan(45) = 1 y = x

OpenStudy (amistre64):

which one of the given points is on that line?

OpenStudy (amistre64):

another way to look at it is: tangent and slope are both defined by y/x so they are the same thing. which point has an inverse tangent of 45 degrees? tan(a) = y/x a = \(tan^{-1}(2/2)\) a = \(45^o\)

OpenStudy (katara11111):

wait so if I do tan-1 would that work with any example or just this one? Also what if it is a larger angle or a negative? But for another question basically I just graph and look?

OpenStudy (amistre64):

the line produced by the angle will always have the basic form: y = mx since m = tan(a) = y/x , then filling in the line equation is a matter of taking the inverse tangent of a given point. so yes, if you know how to graph the angle then you can determine any point along the line that is formed

OpenStudy (amistre64):

if just given a degree, then replace m by tan y = tan(45) x y = 1x

OpenStudy (katara11111):

y = tan (m)x ? Then how do I know y and x? I think I am missing something simple. I'm sorry.

OpenStudy (amistre64):

you determine y and x from given options. the key is relating the trig function "tangent" to the definition of the slope of a line "m". slope is defined as y/x tangent is defined as y/x lets use a 60 degree angle for an example, we want to determine the equation: y = mx y = tan(a) x y = tan(60) x y = sqrt(3)/1 x this is the usual form of a line that everyone is fond of seeing. now we can take any of the given points and test if they fit the line does 2,2 fit?: 2 = sqrt(3) * 2 = 2sqrt(3) since 2 does not equal 2sqrt(3) this point is not a line of 60 degrees does 1, sqrt(3): sqrt(3) = sqrt(3) * 1 = sqrt(3) since sqrt(3) equals sqrt(3) this point IS on a line of 60 degrees.

OpenStudy (amistre64):

the inverse tangent method would also suffice: you are given that: m = y/x tan(45) = y/x 45 = tan^-1 (y/x) test out the given points. it might help to recall that a point is defined as (x,y)

OpenStudy (katara11111):

so if I can plug it in equal to the y and it doesn't work then it isn't right. I'm going to try an example could you tell me if I did it correctly?

OpenStudy (katara11111):

Thank you! I figured out! :)

OpenStudy (amistre64):

yay! :) i think the site went down for a bit the last time ....

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