Question

Solve for x-x^3=2x^4+3x^2-5

Answer 1

Anybody? I seriously cant do this..

Answer 2

1. add like terms... there are none
2. put in terms of LHS = 0
3. factorize
4. solve

Answer 3

Here are the options:

A)X=-.87, X=1.16
B)X=-1.56, X=1
C)X=+-1
D)X=0

Answer 4

step 1 . done

step 2.
-2x^4 - x^3 - 3x^2 + x + 5 = 0

follow so far dude?

Answer 5

Yep, i think so.

Answer 6

step 3.

- ((x - 1) (x + 1) (2x^2 + x + 5)) = 0

which is the same as writing

((x - 1) (x + 1) (2x^2 + x + 5)) = 0 (ie if u multiply both sides of the equals sign by -1 = above answer

so as (x - 1) (x + 1) (2x^2 + x + 5) = 0
either (x - 1) = 0
or (x + 1) = 0
or (2x^2 + x + 5) = 0

Answer 7

now at your level you only need to be focusing on real solutions, not complex/ imaginary numbers, so you can ignore the line:
or (2x^2 + x + 5) = 0

so your answers are either:
(x - 1) = 0, so x must = +1
(x + 1) = 0, so x must equal -1

Answer 8

all good dude?

Answer 9

yes, thanks so much!

Answer 10

always welcome man, slaters