Question

The equation of a line in the xy-plane with slope -1 passing through the point with coordinates (x,y)=(3,0) is

Answer 1

\(y-y_1=m(x-x_1)\) put \(m=-1, x_1=3, y_1=0\)

Answer 2

are you still having problems ?

Answer 3

satellite pretty much just explained how to solve this using the point slope formula.
Let me get you started...
y - y1 = m(x - x1) using slope(m) -1 and points (3,0)
y - 0 = -1(x - 3).....don't forget to distribute the -1 through the parenthesis.
If you are still having problems, check this out....
http://www.purplemath.com/modules/strtlneq2.htm

Answer 4

whats the answer

Answer 5

are you even gonna try to do this ?

Answer 6

lets do this together....
y - 0 = -1(x - 3)
can you distribute the -1 through the parenthesis ?

Answer 7

the answer is C usually

Answer 8

your messing with my brain satellite...lol

Answer 9

can you distribute the -1 through the parenthesis, @jahvoan ?

Answer 10

y=-x+3

Answer 11

got it

Answer 12

could it be x-y=3

Answer 13

BINGO......you got it :)
y = -x + 3
or in standard form it is x + y = 3

Answer 14

is x-y=3 wrong?

Answer 15

yes.....y = -x + 3
if you are going to put this in standard form, and move the x to the other side, then you have to change signs on the x.
Let me show you...
y = -x + 3 (add x to both sides)
y + x = -x + x = 3 (combine like terms)
y + x = 3
Do you understand how I did that ?

Answer 16

as you can see, the x's on the right side cancel each other out.

Answer 17

your answer is :
In slope intercept form y = -x + 3
In standard form y + x = 3
I do not know which form your teacher is asking for,but both of these answers are correct.