Question

how would you solve this homogeneous diff. equation?

Answer 1

\[x(x+y)y \prime-y(x-y)=0\]

Answer 2

thanks @Loser66

Answer 3

what? lol

Answer 4

i tried substituting u = y/x

Answer 5

im sort of messing up in the algebra part i think.

Answer 6

i got \[(y/x)((y/2x)+1)=c\]

Answer 7

\[x(x+y)y'-y(x-y)=0\\y'=\frac{y(x-y)}{x(x+y)}\\\quad=\frac{y(1-y/x)}{x(1+y/x)}\]

Answer 8

now substitute u = y/x

Answer 9

oh ok thanks!