Question

The equation of circle having a diameter with endpoints (-3, 1) and (5, 7) is

Answer 1

The answers available are
(x - 4)² + (y - 3)² = 25
(x - 1)² + (y - 4)² = 25
(x - 1)² + (y - 4)² = 100

Answer 2

distance between end points of diameter will be twice the radius,
so first find the distance between (-3, 1) and (5, 7)

Answer 3

Distance between points (x1,y1) and (x2,y2) is
\(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)

Answer 4

So (-3-5)^2 + (1-7)^2

Answer 5

yes, simplify and take square root..

Answer 6

But I don't understand how I'd end up with one o these as an answer
(x - 4)² + (y - 3)² = 25
(x - 1)² + (y - 4)² = 25
(x - 1)² + (y - 4)² = 100

Answer 7

*of

Answer 8

when you get the radius, just square it.
for radius you will first need diameter...

Answer 9

I'm confused.d..q.wdpfqwjfwpefv.:(

Answer 10

(-3-5)^2 + (1-7)^2 = 8^2 +6^2 = 100
its square root will be 10
radius = 5
to get the centre, find the midpoint of (-3, 1) and (5, 7)
can u ?

Answer 11

I dontknow how to do any of it.. I feel sooo dumb.

Answer 12

don't know*

Answer 13

mid-point we did recently, right ?
just find the average of co-ordinates...

Answer 14

(-3+5)/2 =... ?
(1+7)/2 =... ?

Answer 15

0
4

Answer 16

actually (1,4)
so, the equation of circle will be
\((x-h)^2+(y-k)^2=r^2 \\ (x-1)^2+(y-4)^2 = 5^2\)

Answer 17

Ok.

Answer 18

So it'd be (x - 4)² + (y - 3)² = 25

Answer 19

?

Answer 20

no....
(x - 1)² + (y - 4)² = 25