Ask your own question, for FREE!
Chemistry 24 Online
OpenStudy (anonymous):

In this redox reaction, identify the oxidizing agent. 2Li+F2 --> 2LiF A) F2 B) Li C) LiF D) O2

OpenStudy (anonymous):

I think its Lithium, Can I get a second opinion

OpenStudy (chmvijay):

oxidizing agent is a substance which accepts electron :)

OpenStudy (anonymous):

so would be C) LiF

OpenStudy (chmvijay):

noooooooo:) the compound which is reduced in this reaction is oxising agent :)

OpenStudy (anonymous):

i don't get it for once I'm confused

OpenStudy (chmvijay):

see oxidation is a lose of electrons which has lost electron in the reactant side can u tell wheather Li or F2

OpenStudy (anonymous):

F2?

OpenStudy (chmvijay):

LOL what is oxidation state of Li on left and right can you tell

OpenStudy (anonymous):

2

OpenStudy (chmvijay):

its not oxidation state LOL

OpenStudy (chmvijay):

ok what is charge on Li u tell me on left and right of the reaction

OpenStudy (anonymous):

False

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!