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Mathematics 18 Online
OpenStudy (darkprince14):

If 2^n > n Can I substitute n for 2^n in the equation? 2*2^n > n+ 1

OpenStudy (shubhamsrg):

yes I guess

OpenStudy (darkprince14):

thanks... but what proof should I use to support it?

OpenStudy (shubhamsrg):

2^n > n so 2^(n+1) > n+1 2. 2^n > n+1 if you'll substitute n for 2^n, 2n > n+1 or n>1 hmm, I dont know what am doing :P sorry, perhaps i am treating the question wrong

OpenStudy (darkprince14):

thanks for your response to my question @shubhamsrg :) It enlightened me. Actually I stopped my computation at 2n>n+1 because I think it could be proven by words since these two are consecutive integers, am I right? Anyway, thanks again!

OpenStudy (shubhamsrg):

2n and n+1 consecutive integers? of course not :|

OpenStudy (darkprince14):

oh, is that so but 2n IS greater than n+1... I mean they'll be consecutive integers if n=1 Sorry for that >_<

OpenStudy (shubhamsrg):

hmm, well glad if I could help where am not too sure if I could? :P

OpenStudy (darkprince14):

thanks again. It really helped me:) mata ne:)

OpenStudy (shubhamsrg):

(Y)

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