Help please, I'll provide a picture.

Question

anonymous · Answer

attachment

goformit100 · Answer

I think C is correct.

anonymous · Answer

thanks

anonymous · Answer

ok, so first of all  let  m1 be the slope of the first line: $$m_{1} = 2/3$$ and m2 the slope of the line you must find.
we know that to perpendicular lines have the slopes defined by the following relation:
$$m_{1} \times m_{2} = -1 => m_{2} = \frac{ -1 }{ m_{1} } = \frac{ -1 }{ \frac{ 2 }{ 3 } } = \frac{ -3 }{ 2 }$$

anonymous · Answer

so the answer will be -3/2x cause when u flip the equation?

ivettef365 · Answer

that is correct

anonymous · Answer

so far we have found the slope of the second line. now, you one more thing: it passes through a point, let's say A(2,-3) . in order to find out the equation here the relation you have to use: 
equation of the second line: $$y - y _{A} = m _{2}(x-x _{A}) => (y - (-3)) = \frac{ -3 }{ 2 } (x-2) => y+3 = \frac{ -3 }{ 2 }x + 3 => y = \frac{ -3 }{ 2 }x$$

ivettef365 · Answer

the slope is -3/2x, you have points (2,-3)
-3 = -3/2(2) + b 
-3 = -3 +b so b = 0 again you have y = -3/2x + 0
which is the same as y = -3/2x