Solve 4/b-1/2b=-7/4
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Yes
\[if~ I~ say~ \frac{4}{b}=\frac{8}{2b}~does~it~make~sense~to~you?\]
ok lets try cross multiplying do u know how?
@greenninjahugs do u?
Yes
So, it'd be 8b = 8b?
@callie2240 and @Loser66
yes
I have to say no with the conclusion. However, one/time . let Callie helps.
Now 8b=-7/4 to solve for b u must divide 8 on both sides understand?
@Loser66 wat u mean no? if u think theres something wrong state it
Yes, so would it be easier for me to convert -7/4 into a decimal?
Wrong way friends.
and will lead to wrong answer!! SURE
then what way? I was taught this way so pls explain
first I need confirm the information. If I misunderstand, I am terribly sorry. \[\huge \frac{4}{b}-\frac{1}{2b}=-\frac{7}{4}\]is it yours?
yes either cross multiply or get the same denominatore which isnt really possible with this one it seems
The negative sign is only on the 7, not the entire fraction.
the same.
where is the asker?
its @greenninjahugs
So, I converted -7/4 into a decimal then I divided it by 8 and came up with -0.21875. My answer choices are 2, 7, 0, and -2., Would my answer be 0?
@greenninjahugs You should reply after my instruction, is it ok? I don't want to go too far before I figure out you don't get
Okay!
\[if~ I~ say~ \frac{4}{b}=\frac{8}{2b}~does~it~make~sense~to~you?\]
No, what did you do to get that?
just time both numerator and denominator by 2
because 2/2 =1
Okay, that makes sense
and now another thing, 8 cookies -1 cookie =? cookie?
don't think it doesn't relate, I 'll try to give you the simplest logic to get the answer.
7 cookies
\[good, ~if~ I~ say,~ \frac{1}{2b} is~cookies~then~I ~have~what?\]
\[\large \frac4b-\frac{1}{2b}=-\frac74\]\[\large \frac{8}{2b}-\frac{1}{2b}=-\frac74 \]\[\large \frac{7}{2b}=-\frac{7}{4} \]\[\large (2b)(-7)=(7)(4)\]\[\large 28 = -14b\]\[\large b = -\frac{28}{14} \]
7 * 1/2b?
\[8* ~cookies(\frac{1}{2b}-1*~cookie(\frac{1}{2b}= 7*~cookies\frac{1}{2b}\]
yah!! so the RHS you have \[\frac{7}{2b}\] right?
Right!
and the left hand side you have \[\frac{-7}{4}\]
make them equal, now \[\frac{7}{2b}=-\frac{7}{2*2}\]does it make sense?
Yes, then I should cross multiply?
Since b= -2,plug that back into your equation to check if it's right. \[\large \frac{4}{-2} -\frac{1}{2(-2)}=-\frac{7}{4} \]\[\large -2 + \frac{1}{4}=-\frac{7}{4}\]
mathematically, you are right, but to me, i just do something like
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