Question

10-6^2/9^2+3^2

Answer 1

sorry didn't mean to cut you off, what did you get?

Answer 2

i got -9 and it told me it was -13/45

Answer 3

is there more to it? I don't see any fractions in the problem

Answer 4

sorry i was looking at the wrong answer? this one didn't have an answer, but im still not sure if i did it right

Answer 5

and the problem is (8-7)-9 ? and nothing else?

Answer 6

if so, then

(8-7)-9

(1)-9

1 - 9

-8


so (8-7)-9 = -8

Answer 7

oh nvm it's different

Answer 8

so in 10-6^2/9^2+3^2 only the 9^2 is under the 6^2 right?

Answer 9

it will probably be best to draw it out

Answer 10

Yah i screwed this whole question up, sorry!

Answer 11

Or use parenthesis.

Answer 12

can you draw out the problem?

Answer 13

yah i can draw it out

Answer 14

thanks

Answer 15

\[\frac{ 10-6^2 }{ 9^2+3^2}\]

Answer 16

thanks that helps

Answer 17

\[\large \frac{ 10-6^2 }{ 9^2+3^2}\]


\[\large \frac{ 10-36 }{ 81+9}\]


\[\large \frac{ -26 }{ 90}\]


\[\large \frac{ 2(-13) }{ 2(45)}\]


\[\large \frac{ -13 }{ 45}\]


\[\large -\frac{ 13 }{ 45}\]


So

\[\large \frac{ 10-6^2 }{ 9^2+3^2} = -\frac{ 13 }{ 45}\]

Answer 18

ok thanks that makes sense!

Answer 19

that's great, yw