How to factor 2x^2+3x
You can factor by x. Which you would get: x(2x + 3) Which you would distribute the x to all the other numbers. Roots: - 3/2 and 0.
There are other forms of that equation.
thats perfect thanks!
Welcome. If you need any information on factoring or another question. I may be able to help.
actually, im having trouble with this one also; 2x^2-13x+20=0
If you wouldnt mind helping me that would be great
I think I just did that on my exam, brb let me check.
Im writing mine tomorrow lol
(x - 4)(2x - 5) = 0 Where the solutions are: 5/2 and 4. You would plug in those to get 0. and foil those two equations together to get 2x^2-13x+20=0
how did you get (x - 4)(2x - 5) = 0?
You break the equation apart. Factor it yourself and you should get 2x^2-13x+20=0
ok i see what u mean but how did you get from 2x^2-13x+20=0 to 2x^2-13x+20=0? How do you break the equation apart?
sorry i meant to 2x^2-13x+20=0 to (x - 4)(2x - 5) = 0
Broke it apart with common factors.
x for 2x^2. 4 for 20.
but 2,13 and 20 dont have anything in common?
You do them by them self.
Their own factor.
so you factor 2x^2 by itself?
In a way yes. By x.
You want to factor it by x, because if you did whole number; you wouldn't get the correct answer.
so you factor x out? im confused
what type is it?
as you see 2x^2 has two x's correct?
ya
x+x= 2x?
You see the 2x is squared, correct?
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