Question

I have 53% Calcium Carbonate and i want to get 10% Calcium Acetate using 80% Acetic Acid?

Answer 1

hmm okay, you're doing:

2CH3COOH + CaCO3 -----> Ca(CH3COO)2 + H2O + CO2

you need 10% Ca(CH3COO)2 ..

simply use the dilution equation, and find how much of each you need.
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V

C1V1=C2V2


I'm assuming that you don't need to take the Ka into account since the reaction of free acetate ions with Ca will drive the dissociation of acetic acid forward.