Question

find an equation of the tangent line to the curve y=3tanx at the point (pi/4,3) Thanks

Answer 1

y = 3 tan x

differentiating w.r.t x

dy/dx = 3 Sec^2 x which is the slope of the curve

slope value m = 3 Sec^2 pi/4 = 3 ( sqr rt 2^2) = 3 x 2 = 6

Equation to tangent @ ( pie/4,3) will be

y -- y' = m ( x -- x' )

y' = 3 and x' = pie/4

y -- 3 = 6 ( x -- pie/4 )

( 6 x -- y) = ( 6 pie -- 3 ) and this is the solution to your question

Answer 2

Thank You very much

Answer 3

what does "--" indicate... is that minus?