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use implicit differentiation to find an equation of the tangent line to the curve at the given point, xsin2y=ycos2x, (pi/2,pi/4) Thanks
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\[x*Cos(2y)*2\frac{dy}{dx}+Sin(2y)=y*(-Sin(2x))*2+Cos(2x)*\frac{dy}{dx}\]
(using the product and chain rules)
Now just plug in the values you know and solve for \[\frac{dy}{dx}\]
so i'm plugging in pi/2 for x and pi/4 for y?
yup. And then solving for \[\frac{dy}{dx}\]
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i got dy/dx=-1
You're probably right. Sorry, I don't feel like plugging it all in, but if you post your work, I'll check it over for you.
i feel confident thank you though for your help
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