Question

Find the functional values f(-9), f(1), and f(8) for the compound function. f(x)={|x-5|, if x<=1 f(x)={1/x+1, if x>1
plz help, tutoring this kid and need the answer and work

Answer 1

f(-9) means you're finding the value of f(x) when x = -9

Answer 2

the rules state that f(x) = |x-5| if x <= 1

so this means

f(x) = |x-5|

f(-9) = |-9-5|

f(-9) = ???

Answer 3

f(1) is found using the same function

Answer 4

f(8) is found using 1/x+1 because this function is used when x > 1

Answer 5

@jim_thompson5910 f(-9)=-14

Answer 6

close

Answer 7

but the absolute value is never negative

Answer 8

f(-9) = |-9-5|

f(-9) = |-14|

f(-9) = 14

Answer 9

o mind if i ask y?

Answer 10

absolute value is basically the distance the number is from 0

Answer 11

-14 is 14 units away from 0 on the number line, so that's why |-14| = 14

Answer 12

the number 76 is 76 units from 0, so |76| = 76

etc etc

Answer 13

oh so f(1)=|-4|
f(1)=4

Answer 14

good

Answer 15

awesome ty

Answer 16

yw

Answer 17

@jim_thompson5910 f(8)=9/8
f(8)=1 1/8

Answer 18

is 1/x+1 really \[\large \frac{1}{x}+1\] or \[\large \frac{1}{x+1}\] ?

Answer 19

the 2nd one

Answer 20

\[\large f(x) = \frac{1}{x+1}\]

\[\large f(8) = \frac{1}{8+1}\]

\[\large f(8) = \frac{1}{9}\]

Answer 21

my bad simple error, it's been a long day lol thanks!!!!!

Answer 22

that's ok, you're welcome