Question

15.

A ball is thrown from ground level with a velocity of 24.5 meters per second. As it starts back down to the ground, it hits a tree at a point 29.4 meters from the ground. How many seconds is the ball in the air before it hits the tree? Use h = vt – 4.9t2 in your work.

A. 1
B. 2
C. 3
D. 5

Answer 1

I solved the problem and I got 4.9(t^2 - 5t + 6) and for t I got 2 seconds or 3 seconds But I can't have both as the answer

Answer 2

Can you please help me

Answer 3

2 seconds

Answer 4

why

Answer 5

plug it into the equation they gave you

Answer 6

But I also plugged in 3 and It works

Answer 7

29.4= 24.5(2)– 4.9(2)^2
29.4=49-19.6
29.4=29.4

Answer 8

oh wait 3 does work huh...

Answer 9

29.4 = 24.5(3) -4.9(3)^2
29.4 = 73.5 - 44.1
29.4 = 29.4

Answer 10

That's why I am confused

Answer 11

did you ask your teacher?

Answer 12

Well I am doing this online Mizzou University Subject so I don't have anyone to ask
But still I think the answer is 3 seconds because it says that it goes at 24.5 meters per second so it would just take it 2 seconds to go up and down and it meets the 29.4 meters s o I think it will be 3 seconds

Answer 13

Yeah that's what I was thinking, this isnt physics right?

Answer 14

I will put 3 as the answer and I will tell you if I got it right in 2 seconds ok

Answer 15

what do you say, should I do it or not

Answer 16

yep do it

Answer 17

Everything got erased I don't know how so I will do this tonight and If you still want to know if I got it I will post it on this

Answer 18

A;right :) I do want to know lol

Answer 19

Hey I did everything all over again and I just submitted it and I got that problem right woo hoo! :D

Answer 20

Thanks man. Thanks for everthing.

Answer 21

*everything

Answer 22

I guess I will see you later. Bye