Find the domain of each function

g(x)=5/x^2-25

ok I really don't remember how to do this, can someone please break it down for me quick and simple

Question

Find the domain of each function

g(x)=5/x^2-25

ok I really don't remember how to do this, can someone please break it down for me quick and simple

anonymous · Answer

$$g(x)=5/( x^2-25)$$

luigi0210 · Answer

set the denominator equal to 0.
x^2-25=0
(x-5)(x+5)=0
------------------------------
x-5=0
x+5=0
------------------------------
x=?

anonymous · Answer

-5? @Luigi0210

luigi0210 · Answer

..and?

anonymous · Answer

5

luigi0210 · Answer

There you go

luigi0210 · Answer

-5, and 5.

anonymous · Answer

ty

luigi0210 · Answer

Yup :P

anonymous · Answer

@Luigi0210 what about on more complicated problems like 

f(t)=3t^2+5t+2

anonymous · Answer

then how could I find the domain again?

jim_thompson5910 · Answer

Keep in mind that the values of 5 and -5 are not part of the domain since they make the denominator zero

basically any number but 5 or -5 is in the domain

luigi0210 · Answer

It would be all real numbers since there are no restrictions

jim_thompson5910 · Answer

this is for the previous problem of 5/(x^2-25)

anonymous · Answer

ok so for the prvious problem domain=-5,5 would be wrong, I thought it was right

jim_thompson5910 · Answer

quite the opposite actually

jim_thompson5910 · Answer

the domain is anything but those two numbers

jim_thompson5910 · Answer

I think you misread Luigi0210's answer a bit

anonymous · Answer

ok and what about the more complicated one?

jim_thompson5910 · Answer

the domain is just the set of numbers that can be plugged into a function (where you will get some result out of it)

anonymous · Answer

that one would be all real numbers

jim_thompson5910 · Answer

since plugging in x = 5 yields a division by zero error, it is NOT in the domain of f(x) = 5/(x^2-25)

jim_thompson5910 · Answer

same thing with x = -5

luigi0210 · Answer

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