Mathematics
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OpenStudy (anonymous):
y=6x-1 and y=1/6x-5= perpendicular right?
y-3=4(x+2) and y+3=4(x+5)+ parallel
right?
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OpenStudy (shamim):
ur given 1st 2 line r not perpendicular
OpenStudy (shamim):
slope of ur 1st line is\[m _{1}=6\]
OpenStudy (luigi0210):
Hm?
The first line is not perpendicular
OpenStudy (shamim):
slope of ur 2nd line is\[m _{2}=\frac{ 1 }{ 6 }\]
OpenStudy (shamim):
and \[m _{1}m _{2}=6 \times \frac{ 1 }{ 6 }=1\]
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OpenStudy (shamim):
it should b \[-1\]for perpendicular
OpenStudy (anonymous):
so neither
OpenStudy (shamim):
ya latest 2 lines r parallel
OpenStudy (shamim):
its true
OpenStudy (shamim):
u can ask any question if u want
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OpenStudy (anonymous):
so its perpendicular
OpenStudy (shamim):
actually u asked 2 questions here
OpenStudy (shamim):
u hv 4 equation of line here
OpenStudy (shamim):
ur 1st pair of lines r not perpendicular
OpenStudy (shamim):
bt ur 2nd pair of lines r parallel
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OpenStudy (anonymous):
the first pair of lines are neither
OpenStudy (shamim):
ur 1st pair of lines r not parallel n not perpendicular
OpenStudy (shamim):
if\[m _{1}=m _{2}\]then those lines r parallel
OpenStudy (shamim):
and if \[m _{1}m _{2}=-1\]then those lines r perpendicular
OpenStudy (anonymous):
ok, i got it.
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OpenStudy (shamim):
ok