Question

Find the slope of the line containing these two points... (0,-4) ; (3,-3) m=?

Answer 1

What's the change in \(y\)? what about change in \(x\)?

Answer 2

im not sure how to do this

Answer 3

slope\[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]

Answer 4

\[m=\frac{ -3-(-4) }{ 3-0 }\]

Answer 5

1/3?

Answer 6

ya

Answer 7

thanks

Answer 8

welcome

Answer 9

i have a few more i just need to plug my numbers in your equation and i should get it right?

Answer 10

ya

Answer 11

ok thanks

Answer 12

if u face any difficulties then knock me please

Answer 13

@shamim is it possible for an answer to be in negative fraction? cause that's what i got for the next one.

Answer 14

ya its possible

Answer 15

k

Answer 16

u know the slope of line is actually\[m= \tan \theta\]

Answer 17

and its possible to get a negative value of \[\tan \theta\]

Answer 18

but if both numerator and denominator are negative should i convert it?

Answer 19

when \[\theta\]is more than 90 degree then the value of\[\tan \theta\] will b negative

Answer 20

(6,4);(11,5) check this for me?

Answer 21

u can cancell both negative

Answer 22

ok i m doing

Answer 23

slope \[m=\frac{ 5-4 }{ 11-6 }\]

Answer 24

or it may b \[m=\frac{ 4-5 }{ 6-11 }=\frac{ -1 }{ -5 }=\frac{ 1 }{ 5 }\]

Answer 25

both r same

Answer 26

no difference

Answer 27

wait i just checked something
on the first problem it seems you didn't plug your numbers right

Answer 28

may b

Answer 29

according to the equation you gave me your figures don't match up

Answer 30

hw?

Answer 31

it's a lesson and i am having a hard time understanding it

Answer 32

anyway u can say\[x _{1}=6,y _{1}=4,x _{2}=11,y _{2}=5\]

Answer 33

or u can say\[x _{1}=11,y _{1}=5,x _{2}=6,y _{2}=4\]

Answer 34

i think i will b able to make ur difficulties as easy

Answer 35

ok that is right i understand that

Answer 36

it is the part where you put your numbers it seems you are not following the equation

Answer 37

even u can write the slope\[m=\frac{ y _{1}-y _{2} }{ x _{1}-x _{2} }\]

Answer 38

yes that is the formula but i see you are putting the numbers in the wrong spots?

Answer 39

when you try to solve

Answer 40

please explain where i did not follow my equation. i wanna clearify if i can

Answer 41

ok i m chexking again

Answer 42

u gave me 2 points (6,4),(11,5)

Answer 43

you changed the equation

Answer 44

i plug in data corractly

Answer 45

i checked

Answer 46

on the first one it is y2-y1
second is y1-y2

Answer 47

please wite where u r feeling confusion

Answer 48

i c

Answer 49

lol

Answer 50

i was telling both r correct

Answer 51

but you still have your numbers in the wrong spot according to the euations

Answer 52

i do see that the equations do turn out to be the same whether negative or positive i understand that

Answer 53

u can write\[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }=\frac{ y _{1}-y _{2} }{ x _{1}-x _{2} }\]

Answer 54

but you are not putting the x1- x2 and y1-y2
you did x2-y2 and x1-y1

Answer 55

that is how you plugged it in if you look back

Answer 56

oh wait lol

Answer 57

(6,4) is not x1 and x2
its is x1 and y1

Answer 58

ok i m pluging again

Answer 59

ah i see where i messed up now it is 1/5

Answer 60

u gave 2 points\[(6,4),(11,5)\]

Answer 61

yah

Answer 62

\[x _{1}=6,y _{1}=4,x _{2}=11,y _{2}=5\]

Answer 63

yes that is where i messed up i got it now thanks

Answer 64

ok

Answer 65

i went back and fixed em i am good now

Answer 66

good

Answer 67

thanks i did em all

Answer 68

goodnight ^_^zzZZZ

Answer 69

good night