Question

(1 / n+ 9) * (3n - 18)/ ( 6 - n)

Answer 1

\[\frac{ 1 }{ n+9 } * \frac{ 3n-18 }{ 6-n }\]

Answer 2

factor out the 3 in the numerator in the second fraction

Answer 3

to get 3 * (n + 9) as the new numerator of the second fraction

Answer 4

does that make sense?

Answer 5

ask me a question if that first step did not make sense

Answer 6

you get 3(1-6)

Answer 7

3(1-n)

Answer 8

not quite, how did you make the horizontal division lines in your first post? I would like to be able to do that to better help explain

Answer 9

i clicked the equation blue button

Answer 10

great, thanks

Answer 11

okay, factoring out 3 from the numerator (the top part) of the second fraction should look like this:

Answer 12

\[\frac{ 3 }{ n+9}\]

Answer 13

\[\frac{ 1 }{ (n + 9) } * \frac{ 3 * (n + 6) }{ (6 - n) }\]

Answer 14

oops, i made a mistake!

Answer 15

do you get \[\frac{ 3 }{ n+9 } \] when you done

Answer 16

close

Answer 17

\[\frac{ 1 }{ (n+9) } * \frac{ 3 *(n - 6) }{ (6 - n) }\]

Answer 18

\[\frac{ 1 }{ (n+9) } * \frac{ 3 * (n - 6) }{ - (n - 6) }\]

Answer 19

\frac{ 1 }{ (n + 9) } * \frac{ 3 }{ -1 }

Answer 20

okay

Answer 21

\[\frac{ 1 }{ (n + 9) } * \frac{ 3 }{ -1 }\]

Answer 22

\[\frac{ 3 }{ -(n+9) }\]

Answer 23

is the final answer

Answer 24

ask me a question if something did not make sense

Answer 25

how you got a negative on the denometor

Answer 26

thanks