Question

Could someone pls help me with this Q. "The line 2y-x+5=0 is a tangent to the curve y=bx+ax^0.5 at point (1,-2). Find the value of a and b.

Answer 1

Calculus, then?
Could you find the derivative of \[\Large y = bx + ax^{0.5}\]?

Answer 2

U mean dy/dx= b+0.5a?

Answer 3

I do mean dy/dx, but there's a little error in your differentiation. :)

Answer 4

i dont see the error

Answer 5

:)
Differentiate this part again:
\[\Large y = bx + \color{red}{ax^{0.5}}\]

and keep in mind that
\[\Large \frac{d}{dx}ax^k = kax^{\color{red}{k-1}}\]

Answer 6

Thankyou!

Answer 7

You can do it from here, then?

Answer 8

i think so

Answer 9

Okay then :)