Question

Find the perimeter of a rectangular object which has a length of square root of 128 feet and a width of square root of 200 feet.

Answer 1

the formula for Perimeter follows \[\large P=2l+2w\] Where \(l = \text{length} \ \text{and} \ w=\text{width}\)

Answer 2

in our problem, \(\large l =\sqrt{128} \ , \ w =\sqrt{200}\)

Answer 3

Understand how it works? :)

Answer 4

Lets see. \[\large P = 2(\sqrt{128})+2(\sqrt{200})\]\[\large P= 2\sqrt{128} + 2\sqrt{200}\]

Answer 5

Is your answer in decimal form?

Answer 6

No decimal form is not accepted

Answer 7

Ok.

Answer 8

No there is no answer choices it is a written response do you want the entire question? ;)

Answer 9

Part 1: Find the perimeter of a rectangular object which has a length of square root of 128 feet and a width of square root of 200 feet. (3 points)

Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form. (2 points)

Part 3: What type of object in your home or school might this be? (1 point)

Answer 10

Oh nevermind. Well,we have to factor out 128 and 200, once we make the stuff inside the square root the same base, we can combine them :)

Answer 11

so \[\large P= 2\sqrt{128} + 2\sqrt{200}= 2\sqrt{2\cdot 2^6}+2\sqrt{2^3\cdot5^2}\]

Answer 12

Do you know how to pull out pairs of numbers from under the parenthesis?

Answer 13

Their is no parenthesis

Answer 14

OK thank you I will solve the rest form here. I appreciate your concern. Thank you very much. :)

Answer 15

not parenthesis,imean square root*

Answer 16

\[\large 2\cdot (2^{1/2}\cdot 2^{6/2})+2\cdot (2^{3/2}\cdot 5^{2/2})\]You see what powers can be easily reduced and pull them out of the parenthesis. \[\large 2\cdot 2^3 (2^{1/2}) + 2\cdot 5 (2^{3/2})\] rewrite \[\large 16\sqrt{2} +10\sqrt{2^3}\] and nw we see that we can pull out one more 2 from 2^3 since 2^3 =2 x 2 x 2 \[\large 16\sqrt{2} +10\sqrt{2\cdot 2\cdot 2}= 16\sqrt{2}+10\cdot 2\sqrt{2} \]Simplify \[\large 16\sqrt{2}+20\sqrt{2} \] the stuff under the square root is the same,or what we call "the base" so we can add these two together. \[\large 16+20\sqrt{2} =?\]

Answer 17

Ok thank you I got the answer thanks .

Answer 18

Awesome :D