Calculus1
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OpenStudy (anonymous):
Can someone check my work for an interval of increasing and decrease problem? It is attached below THANK YOU!
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OpenStudy (anonymous):
OpenStudy (magbak):
It is correct
OpenStudy (anonymous):
Are my cps and first derivative test ok?
OpenStudy (anonymous):
@Jhannybean ?
OpenStudy (anonymous):
OOOO my gosh
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OpenStudy (anonymous):
wait that is the second derivative
OpenStudy (anonymous):
I wrote the first derivative on my paper
OpenStudy (anonymous):
f(x) is x^4-8x^3+18x^2-16x+5
OpenStudy (anonymous):
Sorry!!!
OpenStudy (jhannybean):
Yeah.... you are right, i was doing it wrong.
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OpenStudy (anonymous):
It is OK!!! Thanks a bunch. When I am graphing it do you take the lowest y coordinate and use infinity to set the range?
OpenStudy (jhannybean):
I set my y min to -27 and y max to 100.
OpenStudy (anonymous):
on your calc?
OpenStudy (jhannybean):
Yeah.
OpenStudy (anonymous):
what about x values
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OpenStudy (jhannybean):
-10 to 10 :)
OpenStudy (anonymous):
I can actually see the graph!! thanks
OpenStudy (jhannybean):
...Yay!!!! :D
OpenStudy (anonymous):
can my range be (infinity,5]
OpenStudy (anonymous):
because 0,5 is my lowest coordinate
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OpenStudy (jhannybean):
your lowest coordinate should be (4,-27) which is your local\absolute min
OpenStudy (anonymous):
is that point even on my graph?
OpenStudy (jhannybean):
yeah can you see your entire graph? :o
OpenStudy (anonymous):
yea. my lowest point is 0,5 on the calc as well lol
OpenStudy (anonymous):
I put my original function in
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OpenStudy (jhannybean):
(0,5) is a local min also, i think.
OpenStudy (anonymous):
yea probably. He doesn't ask for it in this question though
OpenStudy (anonymous):
if that is the case then is my answer acceptable
OpenStudy (jhannybean):
mmhmm :)
OpenStudy (anonymous):
Thanks a bunch
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OpenStudy (jhannybean):
Btw, which calc book are you using?It isn't stewarts is it?
OpenStudy (anonymous):
calc of a single variable
OpenStudy (anonymous):
early transcendental edition
OpenStudy (jhannybean):
I meant, who is the author? :D