I'm not sure how to solve this equation y' (2x - 2y - 4) = 2x + 7y + 5
we are studying linear differential equations at the moment
Umm what methods do you know as of yet
Are you familiar with the method Exact equations?
we've been doing integrating factors and homogeneous equations, this question was the last one the set homework.
exact equations? no
How about substitutions?
ah - it was mentioned in our last lecture - do you think it would help here?
Ya I do think so actually
Wait let me see one sec
i'll havev to check in my written notes.
i must admit i'm struggling a bit with this topic
You can definitely use substitution just gotta figure it out
I am having a hard time finding a substitution
you can write this equation as (2x - 2y - 4) dy = (2x + 7y + 5) dx have you seen the technique where you shift the origin so that the coefficients are zero: solve 2x - 2y - 4 =0 2x + 7y =0 to find (1,-1) let u= x -1 and v = y+1 to get (2u - 2v) dv = (2u + 7v) du this can be solved using another substitution: v = w u , dv = w du + u dw
another method is use the substitution u = 2x -2y -4 du = 2 dx -2 dy v = 2x + 7y + 5 and dv = 2 dx + 7 dy solve for dx and dy in terms of du and dv this should get you to something you can solve
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