Question

how do you get rid of the exponent in x^4=1?

Answer 1

on order to solve for x

Answer 2

by sqrt on both sides

Answer 3

even though its x^4 and not x^2?

Answer 4

x^4 = 1
x^2 = -1 or 1
x = -1,1,-i,i

Answer 5

so if i square root both sides i get x= 1?

Answer 6

No if you sqrt both sides you get $x^2={\plusminus}1$

Answer 7

how do i get the final answer?

Answer 8

Then square root both sides again.

The sqrt of 1 is \[{\plusminus}1\]
The sqrt of -1 is \[{\plusminus}i\]

But of you guys haven't learner about \[i\] yet, then just say \[{plusminus}1\]. But if you do know about I, it would be useful to learn about DeMoivre's Theorem.

Answer 9

okay, thank you so much!

Answer 10

the plus minus \(\pm\)

is just "\pm" in\(\LaTeX\)

Answer 11

Haha, thanks, I was wondering why that came out so funky. Also, is there any way to put it unlike?

Answer 12

*inline

Answer 13

\ ( latex here \ )

but don't put a space between \ and (

Answer 14

Ok, \(thanks\)

Answer 15

http://openstudy.com/study#/groups/LaTeX%20Practicing!%20%3A)

Answer 16

what okay, I have a question. So I was trying to find x in order to solve this problem:

Find the solutions to 0 ≥ x4 – 1 by graphing y ≥ x4 – 1 by hand.

So now I'm plugging in \[\pm i\] into y ≥ x4 – 1 but I dont know how to lol sorry

Answer 17

I think they expect only the real solutions to be plotted

Answer 18

Thats what I thought, so how do I solve it without using i

Answer 19

The want you to graph y= x^4 -1

can you do that ?

Answer 20

Thats it, I think

Answer 21

It does not look like you did it by hand, but that is the curve
now identify where y ≤ 0
(where y = x^4 – 1 )

Answer 22

i did it by hand on my paper I just didnt know how else to show it to you lol thats it with y </= 0

Answer 23

the curve is ≤ 0 between -1 ≤ x ≤ 1

Answer 24

Find the solutions to 0 ≥ x^4 – 1 is -1 ≤ x ≤ 1

Answer 25

alright, thank you!!