Question

Help.....

Answer 1

ok will do

Answer 2

or try to

Answer 3

this one i can not help you with......

Answer 4

awww y??

Answer 5

i'm not good with DNA sequances

Answer 6

me neither

Answer 7

im not good with dna sequenceseither

Answer 8

well I have to go guys so c ya later

Answer 9

they're not DNA sequences :P they're phenotypes of certain alleles in genes

Answer 10

well doesnt that have to do with DNA

Answer 11

Capital C is most likely the affected gene and lowercase c is the normal.
Females have XX and males have XY
Since the father has normal blood clotting, his genotype will be \(\sf\Large X^cY\), not \(\sf\Large X^CY\)
So the answer will either be C or D
Since the disease needs 2 affected genes in females to come to expression, the mother needs \(\sf\Large X^CX^C\) (homozygote = 2 of the same) to have the disease. But the mother is carrier, this means she's heterozygote: \(\sf\Large X^CX^c\) (heterozygote = 2 different).
She can pass on the disease to her children but it's rare that women will have the disease.

Answer 12

whoa O_O @thomaster

Answer 13

It does have to do with DNA. But to solve this problem, all we really need to understand is how sex-linked diseases are passed down.