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Mathematics 9 Online
OpenStudy (anonymous):

Help multiplication problem i think? (pic below)

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you multiply to get the answer? im confused with this but i think its easy.

OpenStudy (anonymous):

|dw:1372196934910:dw|

OpenStudy (anonymous):

you know this |dw:1372196969684:dw| you want to know this |dw:1372196991584:dw|

OpenStudy (anonymous):

i divide?

OpenStudy (anonymous):

its not as easy as multiplying or dividing unless it was lined up like this |dw:1372197086106:dw|

OpenStudy (anonymous):

Hmm.. so how do i solve this then??

OpenStudy (anonymous):

determine the "?" length

OpenStudy (anonymous):

how do i do that?

OpenStudy (anonymous):

does pythagorean theorem sound familiar?

OpenStudy (anonymous):

a+b=c

OpenStudy (anonymous):

\[a^2+b^2 = c^2\] not a + b =c

OpenStudy (rmrjr22):

a^2 +b^2 = C^2

OpenStudy (anonymous):

i have less then four minutes to solve this. Can anyone else help me out, cuz im not getting it?

OpenStudy (anonymous):

|dw:1372197400459:dw|

OpenStudy (anonymous):

we can determine c = 4 and b = 2 through basic geometry so determine a

OpenStudy (anonymous):

i dont get how a triangle is going to help when i have a shape that is not a triangle at all..

OpenStudy (anonymous):

multiply a by 2 which gives you the "? " length

OpenStudy (anonymous):

8 x 2= 16

OpenStudy (anonymous):

|dw:1372197495074:dw|

OpenStudy (anonymous):

so my answer would be 2?

OpenStudy (anonymous):

no...

OpenStudy (anonymous):

using pythagorean theorem, determine a, if b= 2 and c =4

OpenStudy (anonymous):

can i pls just get the answer. im out of time.

OpenStudy (rmrjr22):

18

OpenStudy (anonymous):

how did you get that answer @rmrjr22 ?

OpenStudy (rmrjr22):

i actually ended up with 12(3)^(1/2)

OpenStudy (rmrjr22):

we have the Radius which is 8 inches long... Cut that in half and that equals the length of each side its a regualr hexagon

OpenStudy (rmrjr22):

so if you use the pythagorean... we have the length of one side, and the hypotnuse

OpenStudy (rmrjr22):

fill in the formula and wala

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