What is the center of the circle that has a diameter whose endpoints are (-3, -5) and (-11, -7)?
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OpenStudy (rmrjr22):
(x-a)^2 + (y-b)^2 = r^2
OpenStudy (rmrjr22):
(x2+x1)/2,(y2+y1)/2=midpoint
OpenStudy (rmrjr22):
plug and play into midpoint formula
OpenStudy (anonymous):
idk what that means haha
OpenStudy (rmrjr22):
(-3,5) = (x1,y1)
(-11,-7) = (x2,y2)
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hero (hero):
If you don't know what it means, use graph paper.
OpenStudy (rmrjr22):
in the formula you are taking the difference of two points then dividing it by two to get the center of those two points you just subtracted from each other...
OpenStudy (anonymous):
-14,2?
OpenStudy (rmrjr22):
-7+ 5 = ?
OpenStudy (rmrjr22):
-7 + (-5) = ? *********
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OpenStudy (anonymous):
-2
OpenStudy (rmrjr22):
-12
OpenStudy (rmrjr22):
sorry my fault
hero (hero):
If you use graph paper, you'll get something like this:
|dw:1372220472229:dw|
hero (hero):
The line segment will intersect a point that is the midpoint of the segment.
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OpenStudy (anonymous):
-7,-6?
hero (hero):
Bingo
OpenStudy (rmrjr22):
Bingo!
hero (hero):
Bingo is one of my favorite games
OpenStudy (rmrjr22):
it will be mine when i get older
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