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Algebra 11 Online
OpenStudy (anonymous):

Please help whats 3^q+3-3^2(3^q)/3(3^q+4)

OpenStudy (asapbleh):

Is this your equation? \[\frac{ 3^{q}+3-3^{2}(3^{9}) }{ (3^{9}+4) }\]

OpenStudy (anonymous):

No q+3 is the exponent and so is the denominator with q+4 and in the numerator in brackets is 3 to the power of q

OpenStudy (asapbleh):

Lemme try this again. \[\frac{ 3^{q+3}-3^{2(3^{q})} }{ 3^{q+4} }\]

OpenStudy (asapbleh):

Is this the right equation?

OpenStudy (anonymous):

Yes and the answer is 2/27

OpenStudy (anonymous):

But how is something I cant figure out!

OpenStudy (anonymous):

Thanks for trying have been stuck with it for the last two days!

OpenStudy (asapbleh):

Oh. But somehow I ended up with -1/4. I guess I did it wrong.

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