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Please help whats 3^q+3-3^2(3^q)/3(3^q+4)
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Is this your equation? \[\frac{ 3^{q}+3-3^{2}(3^{9}) }{ (3^{9}+4) }\]
No q+3 is the exponent and so is the denominator with q+4 and in the numerator in brackets is 3 to the power of q
Lemme try this again. \[\frac{ 3^{q+3}-3^{2(3^{q})} }{ 3^{q+4} }\]
Is this the right equation?
Yes and the answer is 2/27
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But how is something I cant figure out!
Thanks for trying have been stuck with it for the last two days!
Oh. But somehow I ended up with -1/4. I guess I did it wrong.
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