Question

I have a list of tuples. Each tuple has two values. I need to be able to return the value of the 0'th (is that a word? hah) index of the tuple that resides in the 0th index of the list. I can easily pull the tuple in which I want to work, from the list, but I can't seem to figure out how to-- in a single step-- pull the first element of a tuple from the first tuple... if anyone can help, I'd greatly appreciate it. Just let me know if my question was too convoluted or incoherent- Thanks!

Answer 1

you could do this

value_a, value_b = tuple_list[0]

Answer 2

The tuple is indexed.

>>> tup=(3,'a',9,'hi')
>>> print tup
(3, 'a', 9, 'hi')
>>> val=tup[0]
>>> print val
3
>>>

Answer 3

Here is another cute one for you:

>>> lis=[(1,2),(3,4),(5,6)] # a list of tuples
>>> print lis
[(1, 2), (3, 4), (5, 6)]
>>> print lis[1] # one element from the list
(3, 4)
>>> print lis[1][0] # only part of a tuple inside the list!
3
>>>

Answer 4

In Python 3.x:
tupList = [(7, 9), (2, 1), (4, 6), (9, 2)]
print(tupList[0][0])

Output:
7

For Python 2.x, use:
print tupList[0][0]