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Help please? :) Find the sum of the infinite geometric series 5 + 5/3 +5/9 +5/27+... if it exists
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it's a infinite gp series.
\[\large \sum_{n=1}^{\infty}5(\frac{1}{3})^{n-1}\]I beleive.
So utilizing definition, \(\ |r|<1\). in our case, \(\large r = \frac{1}{3}\) sO we have found that it converges. Then we use our sum, \(\large \frac{a}{1-r}\) \[\large a= 5 \ , \ r = \frac{1}{3}\]\[\large \frac{5}{1-\frac{1}{3}} = \frac{5}{2/3} = \frac{5 \cdot 3}{2} = ?\]
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